What is the output voltage change per 50 mm based on the "Teach in procedure" of the ultrasonic sensor?

The output voltage change of 0.2 V/mm as established during the "Teach in procedure" of the ultrasonic sensor indicates how the sensor calibrates itself to reflect distance changes in a measurable way. Ultrasonic sensors typically function based on the time taken for sound waves to return after reflecting off an object. When the sensor is configured during the teaching phase, it learns the relationship between the distance to the target object and the corresponding output voltage.

For every 1 mm change in distance, output voltage is adjusted by 0.2 V. Thus, for a distance change of 50 mm, the output voltage would change by 50 mm multiplied by the response of 0.2 V/mm, resulting in a total change of 10 V. This precise scaling ensures that users can predict the sensor’s output based on object proximity accurately.

Understanding this calibration process is vital for practical applications, helping in scenarios like level measurement, distance determination, and object detection, which rely on the proportional relationship between distance and output voltage of the sensor.